2(x^2+4)-5=7

Solution for 2(x^2+4)-5=7 equation:

Simplifying
2(x2 + 4) + -5 = 7

Reorder the terms:
2(4 + x2) + -5 = 7
(4 * 2 + x2 * 2) + -5 = 7
(8 + 2x2) + -5 = 7

Reorder the terms:
8 + -5 + 2x2 = 7

Combine like terms: 8 + -5 = 3
3 + 2x2 = 7

Solving
3 + 2x2 = 7

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2x2 = 7 + -3

Combine like terms: 3 + -3 = 0
0 + 2x2 = 7 + -3
2x2 = 7 + -3

Combine like terms: 7 + -3 = 4
2x2 = 4

Divide each side by '2'.
x2 = 2

Simplifying
x2 = 2

Take the square root of each side:
x = {-1.414213562, 1.414213562}